Line In Cubic Even case #
We say that a linear solution satisfies the lineInCubic
property
if the line through that point and through the two different planes formed by the basis of
LinSols
lies in the cubic.
We show that for a solution all its permutations satisfy this property, then there exists a permutation for which it lies in the plane spanned by the first part of the basis.
The main reference for this file is:
This lemma states that for a given S
of type (PureU1 (2 * n.succ)).AnomalyFreeLinear
and
a proof h
that the line through S
lies on a cubic curve,
for any functions g : Fin n.succ → ℚ
and f : Fin n → ℚ
, if S.val = P g + P! f
,
then accCubeTriLinSymm.toFun (P g, P g, P! f) = 0
.
A LinSol
satisfies LineInCubicPerm
if all its permutations satisfy lineInCubic
.
Equations
- PureU1.Even.LineInCubicPerm S = ∀ (M : (PureU1.FamilyPermutations (2 * n.succ)).group), PureU1.Even.LineInCubic (((PureU1.FamilyPermutations (2 * n.succ)).linSolRep M) S)
Instances For
If lineInCubicPerm S
then lineInCubic S
.
If lineInCubicPerm S
then lineInCubicPerm (M S)
for all permutations M
.