A electrostatics of a point particle in 3d. #
In this module we derive properties of the electrostatics of a point particle of
charge q
sitting in 3
d space.
i. Key results #
- The electric potential is given by
electricPotential q ε r₀
. - The electric field is given by
electricField q ε r₀
. - Gauss's law is given in
gaussLaw
. - Faraday's law is given in
faradaysLaw
.
ii. References #
- The proof of Gauss' law in this module follows: https://math.stackexchange.com/questions/2409008/
A. Definitions #
We start by stating the charge distribution, electric potential and electric field of the point particle. Later on in this module we will prove that these definitions are correct, by showing they satisfy the necessary physical properties.
We have the following definitions:
- The
chargeDistribution
isq δ(r-r₀)
. - The
electricPotential
is(q/(4 * π * ε)) • ‖r - r₀‖⁻¹
. - The
electricField
is(q/(4 * π * ε)) • ‖r - r₀‖⁻¹ ^ 3 • (r - r₀)
.
The charge distribution of a point particle of charge q
in 3d space sitting at the r₀
.
In the physicists notation this corresponds to the 'function' q δ(r-r₀)
.
Equations
Instances For
The electric potential of a point particle of charge q
in 3d space sitting at the r₀
.
In physics notation this corresponds to the 'function' (q/(4 * π * ε)) • ‖r - r₀‖⁻¹
.
Here it is defined as the distribution corresponing to that function.
Equations
Instances For
The electric field of a point particle of charge q
in 3d space sitting at r₀
.
In physics notation this corresponds to the 'function'
(q/(4 * π * ε)) • ‖r - r₀‖⁻¹ ^ 3 • (r - r₀)
.
Here it is defined as the distribution corresponding to that function.
Equations
Instances For
B. Properties for q = 0
#
We first prove that the charge distribution, electric potential and electric field are all zero when the charge of the particle is zero.
C. Translations #
We now prove that the charge distribution, electric potential and electric field
for the point particle at r₀
is just the translation of the charge distribution,
electric potential and electric field for the point particle located at 0
.
D. Proving the gradient of the potential is the electric field #
We now prove that the electric field is equal to the negative gradient of the potential,
i.e. E = -∇φ
.
D.1. Reducing the problem to showing an integral is zero #
Until the very end of this problem we will implicitly assume that r₀ = 0
.
We generalize at the end.
The first step of our proof is to show that E = -∇φ
if for any Schwartz map η
and direction y
the integral
∫ r, d_y η r * ‖r‖⁻¹ + η r * -⟪(‖r‖ ^ 3)⁻¹ • x, r⟫_ℝ = 0
is equal to zero.
Recall that a 'Schwartz map' is a smooth function which, along with all it's derivatives, decays fast. It's presence here is because the electric field and potential are defined as distributions, and distributions are defined by how they act on Schwartz maps.
The relation E = -∇φ
holds for the point particle if the integral
∫ x, d_y η x * ‖x‖⁻¹ + η x * -⟪(‖x‖ ^ 3)⁻¹ • x, y⟫_ℝ = 0
is zero.
D.2. A smooth approximation to ‖r‖⁻¹
#
Notice that in the integral
∫ r, d_y η r * ‖r‖⁻¹ + η r * -⟪(‖r‖ ^ 3)⁻¹ • x, r⟫_ℝ = 0
the integrand is has the structure of the total derivative of the function
η r * ‖r‖⁻¹
in the direction y
, i.e. d_y (η r * ‖r‖⁻¹)
.
However, this doesn't quite work because ‖r‖⁻¹
is not differentiable at r = 0
.
To get around this we define a sequence of functions, which for n : ℕ
are given by
potentialLimitSeries n r = (‖r‖ ^ 2 + 1/(n + 1))^ (-1/2 : ℝ)
.
The overall aim will be to write ∫ r, d_y η r * ‖r‖⁻¹ + η r * -⟪(‖r‖ ^ 3)⁻¹ • x, r⟫_ℝ
as the limit of the integrals
∫ r, d_y η r * potentialLimitSeries n r + η r * d_y (potentialLimitSeries n) r y
as n → ∞
, and then show that each of these integrals is zero because they
are integrals of total derivatives of differentiable functions.
A series of functions whose limit is the ‖x‖⁻¹
and for which each function is
differentiable everywhere.
Equations
Instances For
Part D.2.I. #
The most important property of potentialLimitSeries
is that it converges to ‖x‖⁻¹
as
n → ∞
. That is, it approximates ‖x‖⁻¹
arbitrarily closely for large enough n
.
Part D.2.II. #
Unlike ‖r‖⁻¹
, importantly the functions potentialLimitSeries n
are
differentiable everywhere.
Part D.2.III. #
The derivative of potentialLimitSeries n
in the direction y
is given by
- (‖r‖^1 + 1/(1 + n))^(-3/2) * ⟪r, y⟫_ℝ
, or equivalently
- (potentialLimitSeries n r) ^ 3 * ⟪r, y⟫_ℝ
.
Part D.2.IV. #
as n → ∞
the limit of the derivative of potentialLimitSeries n
in the direction y
is
-⟪(‖x‖ ^ 3)⁻¹ • x, y⟫_ℝ
. This is exactly the derivative of ‖x‖⁻¹
in the direction y
, when it exists (i.e. when x ≠ 0
).
Part D.2.V #
Because we are integrating, we need to show some integrability and measurability properties
of potentialLimitSeries
and it's derivative.
We first show that they are almost everywhere strongly measurable.
Part D.2.VI. #
We now show that potentialLimitSeries
satisfies the condition IsDistBounded
.
Along with the fact it is almost everywhere strongly measurable, this means
it can be made into a tempered distribution, but for our purposes means that it is
integrable when multiplied by a Schwartz map.
There are a number of precursory lemmas first.
Part D.2.VII. #
In a similar fashion, and for the same reason,
we now show that the derivative of potentialLimitSeries
satisfies the condition IsDistBounded
.
D.3. A series of integrals #
We now show that the integral
∫ r, d_y η r * ‖r‖⁻¹ + η r * -⟪(‖r‖ ^ 3)⁻¹ • x, r⟫_ℝ
is the limit of the integrals
∫ r, d_y (η r * potentialLimitSeries n r)
as n → ∞
.
Part D.3.I. #
We first define a series of functions which are the integrands of
∫ r, d_y (η r * potentialLimitSeries n r)
.
These functions are potentialLimitSeriesFDerivSchwartz y η n r
.
A series of functions of the form fderiv ℝ (fun x => η x * potentialLimitSeries n x) x y
.
Equations
- One or more equations did not get rendered due to their size.
Instances For
Part D.3.II. #
We show that these integrands converge to the integrand of
∫ r, d_y η r * ‖r‖⁻¹ + η r * -⟪(‖r‖ ^ 3)⁻¹ • x, r⟫_ℝ
as n → ∞
.
Part D.3.III. #
We use 'Lebesgue dominated convergence theorem' to show that the integrals
∫ r, d_y (η r * potentialLimitSeries n r)
converge to the integral
∫ r, d_y η r * ‖r‖⁻¹ + η r * -⟪(‖r‖ ^ 3)⁻¹ • x, r⟫_ℝ
as n → ∞
.
This requires some measurability properties of potentialLimitSeriesFDerivSchwartz
and uses the integrability properties of potentialLimitSeries
and
its derivative shown above.
D.4. The limit of the series of integrals is zero #
Above we showed that the limit of the integrals
∫ r, d_y (η r * potentialLimitSeries n r)
as n → ∞
is
∫ r, d_y η r * ‖r‖⁻¹ + η r * -⟪(‖r‖ ^ 3)⁻¹ • x, r⟫_ℝ
.
We now show that this same limit is zero.
Part D.4.I. #
The integral
∫ r, d_y (η r * potentialLimitSeries n r)
is zero for each n : ℕ
.
This follows because this integrand is the total derivative of a differentiable function.
Part D.4.II. #
From part D.4.I it follows that the limit of the integrals
∫ r, d_y (η r * potentialLimitSeries n r)
as n → ∞
is zero, since each
individual integral is zero.
D.5. E = -∇ V for a particle at the origin #
We now put everything together. In part D.1 we showed that E = -∇ V
follows from the integral
∫ r, d_y η r * ‖r‖⁻¹ + η r * -⟪(‖r‖ ^ 3)⁻¹ • x, r⟫_ℝ = 0
for all Schwartz maps η
and
directions y
.
In part D.3 we showed that this integral is the limit of the integrals
∫ r, d_y (η r * potentialLimitSeries n r)
as n → ∞
.
In part D.4 we showed that this limit is zero, and therefore this integral itself must be zero.
It follows that E = -∇ V
for a particle at the origin.
D.6. E = -∇ V for a particle at r₀ #
The general case of a particle at r₀
follows from the case of a particle at the origin
by using that the gradient commutes with translation.
E. Faraday's law #
Faraday's law, which says that ∇ × E = 0
,
is an immediate consequence of the fact that E = -∇ V
, because
the curl of a gradient is always zero.
F. Gauss' law #
We now prove Gauss' law for a point particle in 3-dimensions. Recall that Gauss' law states that
the divergence of the electric field is equal to the charge density divided by the permittivity,
i.e. ∇ • E = ρ/ε
.
In this case, this result is related to the sometimes confusing fact that
∇ • ((‖r‖⁻¹) ^ 3 • r) ∝ δ(r)
.
We first prove Gauss' law for a point particle at the origin, and then use translation to
prove it for a point particle at r₀
.
F.1. Gauss' law for a point particle at the origin #
The proof of Gauss' law for a point particle at the origin follows the proof given here: https://math.stackexchange.com/questions/2409008/
We highlight the main steps of the proof here (the below comments also appear in-line within the proof) :
- Step 1:
∇ ⬝ E = 1/ε ρ
if for all Schwartz mapsη
,∇ ⬝ E η = (1/ε ρ) η
. - Step 2: We focus on rewriting the LHS, by definition it is equal to
- ∫ d³r ⟪(q/(4 * π * ε)) • ‖r‖⁻¹ ^ 3 • r, (∇ η) r⟫
- Step 3: We rearrange the integral to
- q/(4 * π * ε) * ∫ d³r ‖r‖⁻¹ ^ 2 * ⟪‖r‖⁻¹ • r), (∇ η) r⟫
- Step 4: We use that
⟪‖r‖⁻¹ • r), (∇ η) r⟫ = (d(η (a • ‖r‖⁻¹ • r))/d a)_‖r‖
to rewrite the integral as- q/(4 * π * ε) * ∫ d³r ‖r‖⁻¹ ^ 2 * (d(η (a • ‖r‖⁻¹ • r))/d a)_‖r‖
. - Step 5: We move over to spherical coordinates rewriting
d³r
asr² dr dn
wheredn
is the integral over the unit vectorsn
. Ind³r
ther
is a vector whilst inr² dr dn
ther
is a scalar (the distance).- q/(4 * π * ε) * ∫ dr² dr dn r⁻¹ ^ 2 * (d(η (a • n))/d a)_r
- Step 6: The integral is rearanged to
- q/(4 * π * ε) * ∫ dn (∫_0^∞ r² dr r⁻¹ ^ 2 * (d(η (a • n))/d a)_r)
- Step 7: The integral is further rearanged to
- q/(4 * π * ε) * ∫ dn (∫_0^∞ dr (d(η (a • n))/d a)_r)
- Step 8: The inner integral
(∫_0^∞ dr (d(η (a • n))/d a)_r)
is an integral over a total derivative of a function which tends to zero at infinity, and so is equal to-η 0
. Thus the integral is equal to- q/(4 * π * ε) * ∫ dn (-η 0)
. - Step 9: The integral
∫ dn
is equal to the surface area of the unit sphere, which is4 * π
. And thus we get after some simplification(q/ε) * η 0
. - Step 10: This is manifestly equal to the right hand side
1/ε ρ η
sinceρ = q δ(r)
, thereby proving the result.
Guass' law for a point particle in 3-dimensions at the origin, that is this theorem states that
the divergence of (q/(4 * π * ε)) • ‖r‖⁻¹ ^ 3 • r
is equal to q • δ(r)
.
F.2. Gauss' law for a point particle at r₀
#
We now show Gauss' law for a point particle at r₀
.
This follows from the case of a point particle at the origin
by using that the divergence commutes with translation.
G. Rotational invaraiance #
We now prove the electric field, charge distribution and potential of a point particle are rotationally invariant.
This is yet to be done, and is a TODO item.
The electrostatic field of a point particle is rotationally invariant.